+*DECK RADB5
+ SUBROUTINE RADB5 (IDO, L1, CC, CH, WA1, WA2, WA3, WA4)
+C***BEGIN PROLOGUE RADB5
+C***SUBSIDIARY
+C***PURPOSE Calculate the fast Fourier transform of subvectors of
+C length five.
+C***LIBRARY SLATEC (FFTPACK)
+C***TYPE SINGLE PRECISION (RADB5-S)
+C***AUTHOR Swarztrauber, P. N., (NCAR)
+C***ROUTINES CALLED (NONE)
+C***REVISION HISTORY (YYMMDD)
+C 790601 DATE WRITTEN
+C 830401 Modified to use SLATEC library source file format.
+C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
+C (a) changing dummy array size declarations (1) to (*),
+C (b) changing definition of variables PI, TI11, TI12,
+C TR11, TR12 by using FORTRAN intrinsic functions ATAN
+C and SIN instead of DATA statements.
+C 881128 Modified by Dick Valent to meet prologue standards.
+C 890831 Modified array declarations. (WRB)
+C 891214 Prologue converted to Version 4.0 format. (BAB)
+C 900402 Added TYPE section. (WRB)
+C***END PROLOGUE RADB5
+ DIMENSION CC(IDO,5,*), CH(IDO,L1,5), WA1(*), WA2(*), WA3(*),
+ + WA4(*)
+C***FIRST EXECUTABLE STATEMENT RADB5
+ PI = 4.*ATAN(1.)
+ TR11 = SIN(.1*PI)
+ TI11 = SIN(.4*PI)
+ TR12 = -SIN(.3*PI)
+ TI12 = SIN(.2*PI)
+ DO 101 K=1,L1
+ TI5 = CC(1,3,K)+CC(1,3,K)
+ TI4 = CC(1,5,K)+CC(1,5,K)
+ TR2 = CC(IDO,2,K)+CC(IDO,2,K)
+ TR3 = CC(IDO,4,K)+CC(IDO,4,K)
+ CH(1,K,1) = CC(1,1,K)+TR2+TR3
+ CR2 = CC(1,1,K)+TR11*TR2+TR12*TR3
+ CR3 = CC(1,1,K)+TR12*TR2+TR11*TR3
+ CI5 = TI11*TI5+TI12*TI4
+ CI4 = TI12*TI5-TI11*TI4
+ CH(1,K,2) = CR2-CI5
+ CH(1,K,3) = CR3-CI4
+ CH(1,K,4) = CR3+CI4
+ CH(1,K,5) = CR2+CI5
+ 101 CONTINUE
+ IF (IDO .EQ. 1) RETURN
+ IDP2 = IDO+2
+ IF((IDO-1)/2.LT.L1) GO TO 104
+ DO 103 K=1,L1
+CDIR$ IVDEP
+ DO 102 I=3,IDO,2
+ IC = IDP2-I
+ TI5 = CC(I,3,K)+CC(IC,2,K)
+ TI2 = CC(I,3,K)-CC(IC,2,K)
+ TI4 = CC(I,5,K)+CC(IC,4,K)
+ TI3 = CC(I,5,K)-CC(IC,4,K)
+ TR5 = CC(I-1,3,K)-CC(IC-1,2,K)
+ TR2 = CC(I-1,3,K)+CC(IC-1,2,K)
+ TR4 = CC(I-1,5,K)-CC(IC-1,4,K)
+ TR3 = CC(I-1,5,K)+CC(IC-1,4,K)
+ CH(I-1,K,1) = CC(I-1,1,K)+TR2+TR3
+ CH(I,K,1) = CC(I,1,K)+TI2+TI3
+ CR2 = CC(I-1,1,K)+TR11*TR2+TR12*TR3
+ CI2 = CC(I,1,K)+TR11*TI2+TR12*TI3
+ CR3 = CC(I-1,1,K)+TR12*TR2+TR11*TR3
+ CI3 = CC(I,1,K)+TR12*TI2+TR11*TI3
+ CR5 = TI11*TR5+TI12*TR4
+ CI5 = TI11*TI5+TI12*TI4
+ CR4 = TI12*TR5-TI11*TR4
+ CI4 = TI12*TI5-TI11*TI4
+ DR3 = CR3-CI4
+ DR4 = CR3+CI4
+ DI3 = CI3+CR4
+ DI4 = CI3-CR4
+ DR5 = CR2+CI5
+ DR2 = CR2-CI5
+ DI5 = CI2-CR5
+ DI2 = CI2+CR5
+ CH(I-1,K,2) = WA1(I-2)*DR2-WA1(I-1)*DI2
+ CH(I,K,2) = WA1(I-2)*DI2+WA1(I-1)*DR2
+ CH(I-1,K,3) = WA2(I-2)*DR3-WA2(I-1)*DI3
+ CH(I,K,3) = WA2(I-2)*DI3+WA2(I-1)*DR3
+ CH(I-1,K,4) = WA3(I-2)*DR4-WA3(I-1)*DI4
+ CH(I,K,4) = WA3(I-2)*DI4+WA3(I-1)*DR4
+ CH(I-1,K,5) = WA4(I-2)*DR5-WA4(I-1)*DI5
+ CH(I,K,5) = WA4(I-2)*DI5+WA4(I-1)*DR5
+ 102 CONTINUE
+ 103 CONTINUE
+ RETURN
+ 104 DO 106 I=3,IDO,2
+ IC = IDP2-I
+CDIR$ IVDEP
+ DO 105 K=1,L1
+ TI5 = CC(I,3,K)+CC(IC,2,K)
+ TI2 = CC(I,3,K)-CC(IC,2,K)
+ TI4 = CC(I,5,K)+CC(IC,4,K)
+ TI3 = CC(I,5,K)-CC(IC,4,K)
+ TR5 = CC(I-1,3,K)-CC(IC-1,2,K)
+ TR2 = CC(I-1,3,K)+CC(IC-1,2,K)
+ TR4 = CC(I-1,5,K)-CC(IC-1,4,K)
+ TR3 = CC(I-1,5,K)+CC(IC-1,4,K)
+ CH(I-1,K,1) = CC(I-1,1,K)+TR2+TR3
+ CH(I,K,1) = CC(I,1,K)+TI2+TI3
+ CR2 = CC(I-1,1,K)+TR11*TR2+TR12*TR3
+ CI2 = CC(I,1,K)+TR11*TI2+TR12*TI3
+ CR3 = CC(I-1,1,K)+TR12*TR2+TR11*TR3
+ CI3 = CC(I,1,K)+TR12*TI2+TR11*TI3
+ CR5 = TI11*TR5+TI12*TR4
+ CI5 = TI11*TI5+TI12*TI4
+ CR4 = TI12*TR5-TI11*TR4
+ CI4 = TI12*TI5-TI11*TI4
+ DR3 = CR3-CI4
+ DR4 = CR3+CI4
+ DI3 = CI3+CR4
+ DI4 = CI3-CR4
+ DR5 = CR2+CI5
+ DR2 = CR2-CI5
+ DI5 = CI2-CR5
+ DI2 = CI2+CR5
+ CH(I-1,K,2) = WA1(I-2)*DR2-WA1(I-1)*DI2
+ CH(I,K,2) = WA1(I-2)*DI2+WA1(I-1)*DR2
+ CH(I-1,K,3) = WA2(I-2)*DR3-WA2(I-1)*DI3
+ CH(I,K,3) = WA2(I-2)*DI3+WA2(I-1)*DR3
+ CH(I-1,K,4) = WA3(I-2)*DR4-WA3(I-1)*DI4
+ CH(I,K,4) = WA3(I-2)*DI4+WA3(I-1)*DR4
+ CH(I-1,K,5) = WA4(I-2)*DR5-WA4(I-1)*DI5
+ CH(I,K,5) = WA4(I-2)*DI5+WA4(I-1)*DR5
+ 105 CONTINUE
+ 106 CONTINUE
+ RETURN
+ END