/** Uses table lookup to match [] type constructs, but\r
only if it can use a lookup table 256 bits in size.\r
It is impractical to make a table if it is too large.\r
- */\r
-public class FastBracket extends Bracket {\r
- int min, max;\r
- BitSet bs;\r
- FastBracket(boolean n) { super(n); }\r
- // This routine can optimize a bracket, possibly\r
- // it will replace it with a FastBracket.\r
- static Bracket process(Bracket b,boolean ignc) {\r
- Vector v = b.v;\r
- b.pv = null;\r
- try {\r
-\r
- // Expand out the vector to make separate\r
- // entries for other cases if ignoreCase is\r
- // turned on.\r
- Vector nv = v;\r
- if(ignc) {\r
- nv = new Vector();\r
- for(int i=0;i<v.size();i++) {\r
- Pattern p = (Pattern)v.elementAt(i);\r
- nv.addElement(p);\r
- if(p instanceof oneChar) {\r
- oneChar oc = (oneChar)p;\r
- nv.addElement(new oneChar(oc.altc));\r
- } else if(p instanceof Range) {\r
- Range ra = (Range)p;\r
- nv.addElement(new Range(ra.altlo,ra.althi));\r
- }\r
- }\r
- }\r
- v = nv;\r
-\r
- // Bubble sort, make sure elements\r
- // are in order. This will allow us\r
- // to merge them.\r
- for(int i=0;i<v.size()-1;i++) {\r
- for(int j=0;j<v.size()-1;j++) {\r
- char c1 = getl(v.elementAt(j));\r
- char c2 = getl(v.elementAt(j+1));\r
- if(c2 < c1) {\r
- Object o = v.elementAt(j);\r
- v.setElementAt(v.elementAt(j+1),j);\r
- v.setElementAt(o,j+1);\r
- }\r
- }\r
- }\r
-\r
- nv = new Vector();\r
- // merge -- remove overlaps\r
- Pattern p = (Pattern)v.elementAt(0);\r
- nv.addElement(p);\r
- for(int i=1;i<v.size();i++) {\r
- if(geth(p)+1 >= getl(v.elementAt(i))) {\r
- Pattern p2 = (Pattern)v.elementAt(i);\r
- char lo = min(getl(p),getl(p2));\r
- char hi = max(geth(p),geth(p2));\r
- nv.setElementAt(p=mkelem(lo,hi),nv.size()-1);\r
- } else {\r
- p = (Pattern)v.elementAt(i);\r
- nv.addElement(p);\r
- }\r
- }\r
-\r
- b.v = v = nv;\r
- } catch(RegSyntax e) {\r
- e.printStackTrace();\r
+ */\r
+public class FastBracket\r
+ extends Bracket\r
+{\r
+ int min, max;\r
+ BitSet bs;\r
+ FastBracket(boolean n)\r
+ {\r
+ super(n);\r
+ }\r
+\r
+ // This routine can optimize a bracket, possibly\r
+ // it will replace it with a FastBracket.\r
+ static Bracket process(Bracket b, boolean ignc)\r
+ {\r
+ Vector v = b.v;\r
+ b.pv = null;\r
+ try\r
+ {\r
+\r
+ // Expand out the vector to make separate\r
+ // entries for other cases if ignoreCase is\r
+ // turned on.\r
+ Vector nv = v;\r
+ if (ignc)\r
+ {\r
+ nv = new Vector();\r
+ for (int i = 0; i < v.size(); i++)\r
+ {\r
+ Pattern p = (Pattern) v.elementAt(i);\r
+ nv.addElement(p);\r
+ if (p instanceof oneChar)\r
+ {\r
+ oneChar oc = (oneChar) p;\r
+ nv.addElement(new oneChar(oc.altc));\r
+ }\r
+ else if (p instanceof Range)\r
+ {\r
+ Range ra = (Range) p;\r
+ nv.addElement(new Range(ra.altlo, ra.althi));\r
+ }\r
}\r
+ }\r
+ v = nv;\r
\r
- // We don't want these things to be empty.\r
- Vector negv = neg(v);\r
- if(v.size()==1) return b;\r
- if(negv.size()==1) {\r
- b.v = negv;\r
- b.neg = !b.neg;\r
- return b;\r
+ // Bubble sort, make sure elements\r
+ // are in order. This will allow us\r
+ // to merge them.\r
+ for (int i = 0; i < v.size() - 1; i++)\r
+ {\r
+ for (int j = 0; j < v.size() - 1; j++)\r
+ {\r
+ char c1 = getl(v.elementAt(j));\r
+ char c2 = getl(v.elementAt(j + 1));\r
+ if (c2 < c1)\r
+ {\r
+ Object o = v.elementAt(j);\r
+ v.setElementAt(v.elementAt(j + 1), j);\r
+ v.setElementAt(o, j + 1);\r
+ }\r
}\r
+ }\r
\r
- // Now consider if we can make a FastBracket.\r
- // Uses a BitSet to do a lookup.\r
- FastBracket fb = newbrack(v,b.neg);\r
- if(fb == null)\r
- fb = newbrack(negv,!b.neg);\r
- if(fb != null) {\r
- fb.parent = b.parent;\r
- fb.next = b.next;\r
- return fb;\r
+ nv = new Vector();\r
+ // merge -- remove overlaps\r
+ Pattern p = (Pattern) v.elementAt(0);\r
+ nv.addElement(p);\r
+ for (int i = 1; i < v.size(); i++)\r
+ {\r
+ if (geth(p) + 1 >= getl(v.elementAt(i)))\r
+ {\r
+ Pattern p2 = (Pattern) v.elementAt(i);\r
+ char lo = min(getl(p), getl(p2));\r
+ char hi = max(geth(p), geth(p2));\r
+ nv.setElementAt(p = mkelem(lo, hi), nv.size() - 1);\r
+ }\r
+ else\r
+ {\r
+ p = (Pattern) v.elementAt(i);\r
+ nv.addElement(p);\r
}\r
+ }\r
\r
- // return the normal Bracket.\r
- return b;\r
+ b.v = v = nv;\r
+ }\r
+ catch (RegSyntax e)\r
+ {\r
+ e.printStackTrace();\r
}\r
\r
- // Build a FastBracket and set bits. If this can't\r
- // be done, return null.\r
- final static FastBracket newbrack(Vector v,boolean neg) {\r
- FastBracket fb = new FastBracket(neg);\r
- fb.v = v;\r
- if(v.size()==0) return null;\r
- fb.min = getl(v.elementAt(0));\r
- fb.max = geth(v.elementAt(v.size()-1));\r
- if(fb.max-fb.min <= 256) {\r
- fb.bs = new BitSet(fb.max-fb.min+1);\r
- for(int i=0;i<v.size();i++) {\r
- Object o = v.elementAt(i);\r
- int min0 = getl(o)-fb.min;\r
- int max0 = geth(o)-fb.min;\r
- for(int j=min0;j<=max0;j++)\r
- fb.bs.set(j);\r
- }\r
- return fb;\r
- }\r
- return null;\r
+ // We don't want these things to be empty.\r
+ Vector negv = neg(v);\r
+ if (v.size() == 1)\r
+ {\r
+ return b;\r
+ }\r
+ if (negv.size() == 1)\r
+ {\r
+ b.v = negv;\r
+ b.neg = !b.neg;\r
+ return b;\r
}\r
\r
- // Negate a sorted Vector. Applying this\r
- // operation twice should yield the same Vector\r
- // back.\r
- final static Vector neg(Vector v) {\r
- try {\r
- Vector nv = new Vector();\r
- if(v.size()==0) {\r
- nv.addElement(new Range((char)0,(char)65535));\r
- return nv;\r
- }\r
- int p0 = getl(v.elementAt(0));\r
- if(p0!=0)\r
- nv.addElement(mkelem((char)0,(char)(p0-1) ));\r
- for(int i=0;i<v.size()-1;i++) {\r
- int hi = getl(v.elementAt(i+1))-1;\r
- int lo = geth(v.elementAt(i))+1;\r
- nv.addElement(mkelem((char)lo,(char)hi));\r
- }\r
- int pN = geth(v.lastElement());\r
- if(pN != 65535)\r
- nv.addElement(mkelem((char)(pN+1),(char)65535));\r
- return nv;\r
- } catch(RegSyntax rs) {\r
- return null;\r
- }\r
+ // Now consider if we can make a FastBracket.\r
+ // Uses a BitSet to do a lookup.\r
+ FastBracket fb = newbrack(v, b.neg);\r
+ if (fb == null)\r
+ {\r
+ fb = newbrack(negv, !b.neg);\r
}\r
- // Make either a Range or oneChar Object, depending on which\r
- // is appropriate.\r
- final static Pattern mkelem(char lo,char hi) throws RegSyntax {\r
- return lo==hi ? (Pattern)(new oneChar(lo)) : (Pattern)(new Range(lo,hi));\r
+ if (fb != null)\r
+ {\r
+ fb.parent = b.parent;\r
+ fb.next = b.next;\r
+ return fb;\r
}\r
- static final char min(char a,char b) {\r
- return a<b ? a : b;\r
+\r
+ // return the normal Bracket.\r
+ return b;\r
+ }\r
+\r
+ // Build a FastBracket and set bits. If this can't\r
+ // be done, return null.\r
+ final static FastBracket newbrack(Vector v, boolean neg)\r
+ {\r
+ FastBracket fb = new FastBracket(neg);\r
+ fb.v = v;\r
+ if (v.size() == 0)\r
+ {\r
+ return null;\r
}\r
- static final char max(char a,char b) {\r
- return a>b ? a : b;\r
+ fb.min = getl(v.elementAt(0));\r
+ fb.max = geth(v.elementAt(v.size() - 1));\r
+ if (fb.max - fb.min <= 256)\r
+ {\r
+ fb.bs = new BitSet(fb.max - fb.min + 1);\r
+ for (int i = 0; i < v.size(); i++)\r
+ {\r
+ Object o = v.elementAt(i);\r
+ int min0 = getl(o) - fb.min;\r
+ int max0 = geth(o) - fb.min;\r
+ for (int j = min0; j <= max0; j++)\r
+ {\r
+ fb.bs.set(j);\r
+ }\r
+ }\r
+ return fb;\r
+ }\r
+ return null;\r
+ }\r
+\r
+ // Negate a sorted Vector. Applying this\r
+ // operation twice should yield the same Vector\r
+ // back.\r
+ final static Vector neg(Vector v)\r
+ {\r
+ try\r
+ {\r
+ Vector nv = new Vector();\r
+ if (v.size() == 0)\r
+ {\r
+ nv.addElement(new Range( (char) 0, (char) 65535));\r
+ return nv;\r
+ }\r
+ int p0 = getl(v.elementAt(0));\r
+ if (p0 != 0)\r
+ {\r
+ nv.addElement(mkelem( (char) 0, (char) (p0 - 1)));\r
+ }\r
+ for (int i = 0; i < v.size() - 1; i++)\r
+ {\r
+ int hi = getl(v.elementAt(i + 1)) - 1;\r
+ int lo = geth(v.elementAt(i)) + 1;\r
+ nv.addElement(mkelem( (char) lo, (char) hi));\r
+ }\r
+ int pN = geth(v.lastElement());\r
+ if (pN != 65535)\r
+ {\r
+ nv.addElement(mkelem( (char) (pN + 1), (char) 65535));\r
+ }\r
+ return nv;\r
+ }\r
+ catch (RegSyntax rs)\r
+ {\r
+ return null;\r
}\r
+ }\r
\r
- // getl -- get lower value of Range object,\r
- // or get value of oneChar object.\r
- final static char getl(Object o) {\r
- Pattern p = (Pattern)o;\r
- if(p instanceof Range)\r
- return ((Range)p).lo;\r
- return ((oneChar)p).c;\r
+ // Make either a Range or oneChar Object, depending on which\r
+ // is appropriate.\r
+ final static Pattern mkelem(char lo, char hi)\r
+ throws RegSyntax\r
+ {\r
+ return lo == hi ? (Pattern) (new oneChar(lo)) : (Pattern) (new Range(lo, hi));\r
+ }\r
+\r
+ static final char min(char a, char b)\r
+ {\r
+ return a < b ? a : b;\r
+ }\r
+\r
+ static final char max(char a, char b)\r
+ {\r
+ return a > b ? a : b;\r
+ }\r
+\r
+ // getl -- get lower value of Range object,\r
+ // or get value of oneChar object.\r
+ final static char getl(Object o)\r
+ {\r
+ Pattern p = (Pattern) o;\r
+ if (p instanceof Range)\r
+ {\r
+ return ( (Range) p).lo;\r
}\r
- // geth -- get higher value of Range object,\r
- // or get value of oneChar object.\r
- final static char geth(Object o) {\r
- Pattern p = (Pattern)o;\r
- if(p instanceof Range)\r
- return ((Range)p).hi;\r
- return ((oneChar)p).c;\r
+ return ( (oneChar) p).c;\r
+ }\r
+\r
+ // geth -- get higher value of Range object,\r
+ // or get value of oneChar object.\r
+ final static char geth(Object o)\r
+ {\r
+ Pattern p = (Pattern) o;\r
+ if (p instanceof Range)\r
+ {\r
+ return ( (Range) p).hi;\r
}\r
+ return ( (oneChar) p).c;\r
+ }\r
\r
- // This is the easy part!\r
- public int matchInternal(int pos,Pthings pt) {\r
- if(pos >= pt.src.length() || Masked(pos,pt)) return -1;\r
- char c = pt.src.charAt(pos);\r
- return (neg ^ (c >= min && c <= max && bs.get(c-min)) ) ?\r
- nextMatch(pos+1,pt) : -1;\r
+ // This is the easy part!\r
+ public int matchInternal(int pos, Pthings pt)\r
+ {\r
+ if (pos >= pt.src.length() || Masked(pos, pt))\r
+ {\r
+ return -1;\r
}\r
+ char c = pt.src.charAt(pos);\r
+ return (neg ^ (c >= min && c <= max && bs.get(c - min))) ?\r
+ nextMatch(pos + 1, pt) : -1;\r
+ }\r
}\r