--- /dev/null
+*DECK RADB3
+ SUBROUTINE RADB3 (IDO, L1, CC, CH, WA1, WA2)
+C***BEGIN PROLOGUE RADB3
+C***SUBSIDIARY
+C***PURPOSE Calculate the fast Fourier transform of subvectors of
+C length three.
+C***LIBRARY SLATEC (FFTPACK)
+C***TYPE SINGLE PRECISION (RADB3-S)
+C***AUTHOR Swarztrauber, P. N., (NCAR)
+C***ROUTINES CALLED (NONE)
+C***REVISION HISTORY (YYMMDD)
+C 790601 DATE WRITTEN
+C 830401 Modified to use SLATEC library source file format.
+C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
+C (a) changing dummy array size declarations (1) to (*),
+C (b) changing definition of variable TAUI by using
+C FORTRAN intrinsic function SQRT instead of a DATA
+C statement.
+C 881128 Modified by Dick Valent to meet prologue standards.
+C 890831 Modified array declarations. (WRB)
+C 891214 Prologue converted to Version 4.0 format. (BAB)
+C 900402 Added TYPE section. (WRB)
+C***END PROLOGUE RADB3
+ DIMENSION CC(IDO,3,*), CH(IDO,L1,3), WA1(*), WA2(*)
+C***FIRST EXECUTABLE STATEMENT RADB3
+ TAUR = -.5
+ TAUI = .5*SQRT(3.)
+ DO 101 K=1,L1
+ TR2 = CC(IDO,2,K)+CC(IDO,2,K)
+ CR2 = CC(1,1,K)+TAUR*TR2
+ CH(1,K,1) = CC(1,1,K)+TR2
+ CI3 = TAUI*(CC(1,3,K)+CC(1,3,K))
+ CH(1,K,2) = CR2-CI3
+ CH(1,K,3) = CR2+CI3
+ 101 CONTINUE
+ IF (IDO .EQ. 1) RETURN
+ IDP2 = IDO+2
+ IF((IDO-1)/2.LT.L1) GO TO 104
+ DO 103 K=1,L1
+CDIR$ IVDEP
+ DO 102 I=3,IDO,2
+ IC = IDP2-I
+ TR2 = CC(I-1,3,K)+CC(IC-1,2,K)
+ CR2 = CC(I-1,1,K)+TAUR*TR2
+ CH(I-1,K,1) = CC(I-1,1,K)+TR2
+ TI2 = CC(I,3,K)-CC(IC,2,K)
+ CI2 = CC(I,1,K)+TAUR*TI2
+ CH(I,K,1) = CC(I,1,K)+TI2
+ CR3 = TAUI*(CC(I-1,3,K)-CC(IC-1,2,K))
+ CI3 = TAUI*(CC(I,3,K)+CC(IC,2,K))
+ DR2 = CR2-CI3
+ DR3 = CR2+CI3
+ DI2 = CI2+CR3
+ DI3 = CI2-CR3
+ CH(I-1,K,2) = WA1(I-2)*DR2-WA1(I-1)*DI2
+ CH(I,K,2) = WA1(I-2)*DI2+WA1(I-1)*DR2
+ CH(I-1,K,3) = WA2(I-2)*DR3-WA2(I-1)*DI3
+ CH(I,K,3) = WA2(I-2)*DI3+WA2(I-1)*DR3
+ 102 CONTINUE
+ 103 CONTINUE
+ RETURN
+ 104 DO 106 I=3,IDO,2
+ IC = IDP2-I
+CDIR$ IVDEP
+ DO 105 K=1,L1
+ TR2 = CC(I-1,3,K)+CC(IC-1,2,K)
+ CR2 = CC(I-1,1,K)+TAUR*TR2
+ CH(I-1,K,1) = CC(I-1,1,K)+TR2
+ TI2 = CC(I,3,K)-CC(IC,2,K)
+ CI2 = CC(I,1,K)+TAUR*TI2
+ CH(I,K,1) = CC(I,1,K)+TI2
+ CR3 = TAUI*(CC(I-1,3,K)-CC(IC-1,2,K))
+ CI3 = TAUI*(CC(I,3,K)+CC(IC,2,K))
+ DR2 = CR2-CI3
+ DR3 = CR2+CI3
+ DI2 = CI2+CR3
+ DI3 = CI2-CR3
+ CH(I-1,K,2) = WA1(I-2)*DR2-WA1(I-1)*DI2
+ CH(I,K,2) = WA1(I-2)*DI2+WA1(I-1)*DR2
+ CH(I-1,K,3) = WA2(I-2)*DR3-WA2(I-1)*DI3
+ CH(I,K,3) = WA2(I-2)*DI3+WA2(I-1)*DR3
+ 105 CONTINUE
+ 106 CONTINUE
+ RETURN
+ END