+++ /dev/null
-*DECK RADB4
- SUBROUTINE RADB4 (IDO, L1, CC, CH, WA1, WA2, WA3)
-C***BEGIN PROLOGUE RADB4
-C***SUBSIDIARY
-C***PURPOSE Calculate the fast Fourier transform of subvectors of
-C length four.
-C***LIBRARY SLATEC (FFTPACK)
-C***TYPE SINGLE PRECISION (RADB4-S)
-C***AUTHOR Swarztrauber, P. N., (NCAR)
-C***ROUTINES CALLED (NONE)
-C***REVISION HISTORY (YYMMDD)
-C 790601 DATE WRITTEN
-C 830401 Modified to use SLATEC library source file format.
-C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
-C (a) changing dummy array size declarations (1) to (*),
-C (b) changing definition of variable SQRT2 by using
-C FORTRAN intrinsic function SQRT instead of a DATA
-C statement.
-C 881128 Modified by Dick Valent to meet prologue standards.
-C 890831 Modified array declarations. (WRB)
-C 891214 Prologue converted to Version 4.0 format. (BAB)
-C 900402 Added TYPE section. (WRB)
-C***END PROLOGUE RADB4
- DIMENSION CC(IDO,4,*), CH(IDO,L1,4), WA1(*), WA2(*), WA3(*)
-C***FIRST EXECUTABLE STATEMENT RADB4
- SQRT2 = SQRT(2.)
- DO 101 K=1,L1
- TR1 = CC(1,1,K)-CC(IDO,4,K)
- TR2 = CC(1,1,K)+CC(IDO,4,K)
- TR3 = CC(IDO,2,K)+CC(IDO,2,K)
- TR4 = CC(1,3,K)+CC(1,3,K)
- CH(1,K,1) = TR2+TR3
- CH(1,K,2) = TR1-TR4
- CH(1,K,3) = TR2-TR3
- CH(1,K,4) = TR1+TR4
- 101 CONTINUE
- IF (IDO-2) 107,105,102
- 102 IDP2 = IDO+2
- IF((IDO-1)/2.LT.L1) GO TO 108
- DO 104 K=1,L1
-CDIR$ IVDEP
- DO 103 I=3,IDO,2
- IC = IDP2-I
- TI1 = CC(I,1,K)+CC(IC,4,K)
- TI2 = CC(I,1,K)-CC(IC,4,K)
- TI3 = CC(I,3,K)-CC(IC,2,K)
- TR4 = CC(I,3,K)+CC(IC,2,K)
- TR1 = CC(I-1,1,K)-CC(IC-1,4,K)
- TR2 = CC(I-1,1,K)+CC(IC-1,4,K)
- TI4 = CC(I-1,3,K)-CC(IC-1,2,K)
- TR3 = CC(I-1,3,K)+CC(IC-1,2,K)
- CH(I-1,K,1) = TR2+TR3
- CR3 = TR2-TR3
- CH(I,K,1) = TI2+TI3
- CI3 = TI2-TI3
- CR2 = TR1-TR4
- CR4 = TR1+TR4
- CI2 = TI1+TI4
- CI4 = TI1-TI4
- CH(I-1,K,2) = WA1(I-2)*CR2-WA1(I-1)*CI2
- CH(I,K,2) = WA1(I-2)*CI2+WA1(I-1)*CR2
- CH(I-1,K,3) = WA2(I-2)*CR3-WA2(I-1)*CI3
- CH(I,K,3) = WA2(I-2)*CI3+WA2(I-1)*CR3
- CH(I-1,K,4) = WA3(I-2)*CR4-WA3(I-1)*CI4
- CH(I,K,4) = WA3(I-2)*CI4+WA3(I-1)*CR4
- 103 CONTINUE
- 104 CONTINUE
- GO TO 111
- 108 DO 110 I=3,IDO,2
- IC = IDP2-I
-CDIR$ IVDEP
- DO 109 K=1,L1
- TI1 = CC(I,1,K)+CC(IC,4,K)
- TI2 = CC(I,1,K)-CC(IC,4,K)
- TI3 = CC(I,3,K)-CC(IC,2,K)
- TR4 = CC(I,3,K)+CC(IC,2,K)
- TR1 = CC(I-1,1,K)-CC(IC-1,4,K)
- TR2 = CC(I-1,1,K)+CC(IC-1,4,K)
- TI4 = CC(I-1,3,K)-CC(IC-1,2,K)
- TR3 = CC(I-1,3,K)+CC(IC-1,2,K)
- CH(I-1,K,1) = TR2+TR3
- CR3 = TR2-TR3
- CH(I,K,1) = TI2+TI3
- CI3 = TI2-TI3
- CR2 = TR1-TR4
- CR4 = TR1+TR4
- CI2 = TI1+TI4
- CI4 = TI1-TI4
- CH(I-1,K,2) = WA1(I-2)*CR2-WA1(I-1)*CI2
- CH(I,K,2) = WA1(I-2)*CI2+WA1(I-1)*CR2
- CH(I-1,K,3) = WA2(I-2)*CR3-WA2(I-1)*CI3
- CH(I,K,3) = WA2(I-2)*CI3+WA2(I-1)*CR3
- CH(I-1,K,4) = WA3(I-2)*CR4-WA3(I-1)*CI4
- CH(I,K,4) = WA3(I-2)*CI4+WA3(I-1)*CR4
- 109 CONTINUE
- 110 CONTINUE
- 111 IF (MOD(IDO,2) .EQ. 1) RETURN
- 105 DO 106 K=1,L1
- TI1 = CC(1,2,K)+CC(1,4,K)
- TI2 = CC(1,4,K)-CC(1,2,K)
- TR1 = CC(IDO,1,K)-CC(IDO,3,K)
- TR2 = CC(IDO,1,K)+CC(IDO,3,K)
- CH(IDO,K,1) = TR2+TR2
- CH(IDO,K,2) = SQRT2*(TR1-TI1)
- CH(IDO,K,3) = TI2+TI2
- CH(IDO,K,4) = -SQRT2*(TR1+TI1)
- 106 CONTINUE
- 107 RETURN
- END