+++ /dev/null
-*DECK RADB5
- SUBROUTINE RADB5 (IDO, L1, CC, CH, WA1, WA2, WA3, WA4)
-C***BEGIN PROLOGUE RADB5
-C***SUBSIDIARY
-C***PURPOSE Calculate the fast Fourier transform of subvectors of
-C length five.
-C***LIBRARY SLATEC (FFTPACK)
-C***TYPE SINGLE PRECISION (RADB5-S)
-C***AUTHOR Swarztrauber, P. N., (NCAR)
-C***ROUTINES CALLED (NONE)
-C***REVISION HISTORY (YYMMDD)
-C 790601 DATE WRITTEN
-C 830401 Modified to use SLATEC library source file format.
-C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
-C (a) changing dummy array size declarations (1) to (*),
-C (b) changing definition of variables PI, TI11, TI12,
-C TR11, TR12 by using FORTRAN intrinsic functions ATAN
-C and SIN instead of DATA statements.
-C 881128 Modified by Dick Valent to meet prologue standards.
-C 890831 Modified array declarations. (WRB)
-C 891214 Prologue converted to Version 4.0 format. (BAB)
-C 900402 Added TYPE section. (WRB)
-C***END PROLOGUE RADB5
- DIMENSION CC(IDO,5,*), CH(IDO,L1,5), WA1(*), WA2(*), WA3(*),
- + WA4(*)
-C***FIRST EXECUTABLE STATEMENT RADB5
- PI = 4.*ATAN(1.)
- TR11 = SIN(.1*PI)
- TI11 = SIN(.4*PI)
- TR12 = -SIN(.3*PI)
- TI12 = SIN(.2*PI)
- DO 101 K=1,L1
- TI5 = CC(1,3,K)+CC(1,3,K)
- TI4 = CC(1,5,K)+CC(1,5,K)
- TR2 = CC(IDO,2,K)+CC(IDO,2,K)
- TR3 = CC(IDO,4,K)+CC(IDO,4,K)
- CH(1,K,1) = CC(1,1,K)+TR2+TR3
- CR2 = CC(1,1,K)+TR11*TR2+TR12*TR3
- CR3 = CC(1,1,K)+TR12*TR2+TR11*TR3
- CI5 = TI11*TI5+TI12*TI4
- CI4 = TI12*TI5-TI11*TI4
- CH(1,K,2) = CR2-CI5
- CH(1,K,3) = CR3-CI4
- CH(1,K,4) = CR3+CI4
- CH(1,K,5) = CR2+CI5
- 101 CONTINUE
- IF (IDO .EQ. 1) RETURN
- IDP2 = IDO+2
- IF((IDO-1)/2.LT.L1) GO TO 104
- DO 103 K=1,L1
-CDIR$ IVDEP
- DO 102 I=3,IDO,2
- IC = IDP2-I
- TI5 = CC(I,3,K)+CC(IC,2,K)
- TI2 = CC(I,3,K)-CC(IC,2,K)
- TI4 = CC(I,5,K)+CC(IC,4,K)
- TI3 = CC(I,5,K)-CC(IC,4,K)
- TR5 = CC(I-1,3,K)-CC(IC-1,2,K)
- TR2 = CC(I-1,3,K)+CC(IC-1,2,K)
- TR4 = CC(I-1,5,K)-CC(IC-1,4,K)
- TR3 = CC(I-1,5,K)+CC(IC-1,4,K)
- CH(I-1,K,1) = CC(I-1,1,K)+TR2+TR3
- CH(I,K,1) = CC(I,1,K)+TI2+TI3
- CR2 = CC(I-1,1,K)+TR11*TR2+TR12*TR3
- CI2 = CC(I,1,K)+TR11*TI2+TR12*TI3
- CR3 = CC(I-1,1,K)+TR12*TR2+TR11*TR3
- CI3 = CC(I,1,K)+TR12*TI2+TR11*TI3
- CR5 = TI11*TR5+TI12*TR4
- CI5 = TI11*TI5+TI12*TI4
- CR4 = TI12*TR5-TI11*TR4
- CI4 = TI12*TI5-TI11*TI4
- DR3 = CR3-CI4
- DR4 = CR3+CI4
- DI3 = CI3+CR4
- DI4 = CI3-CR4
- DR5 = CR2+CI5
- DR2 = CR2-CI5
- DI5 = CI2-CR5
- DI2 = CI2+CR5
- CH(I-1,K,2) = WA1(I-2)*DR2-WA1(I-1)*DI2
- CH(I,K,2) = WA1(I-2)*DI2+WA1(I-1)*DR2
- CH(I-1,K,3) = WA2(I-2)*DR3-WA2(I-1)*DI3
- CH(I,K,3) = WA2(I-2)*DI3+WA2(I-1)*DR3
- CH(I-1,K,4) = WA3(I-2)*DR4-WA3(I-1)*DI4
- CH(I,K,4) = WA3(I-2)*DI4+WA3(I-1)*DR4
- CH(I-1,K,5) = WA4(I-2)*DR5-WA4(I-1)*DI5
- CH(I,K,5) = WA4(I-2)*DI5+WA4(I-1)*DR5
- 102 CONTINUE
- 103 CONTINUE
- RETURN
- 104 DO 106 I=3,IDO,2
- IC = IDP2-I
-CDIR$ IVDEP
- DO 105 K=1,L1
- TI5 = CC(I,3,K)+CC(IC,2,K)
- TI2 = CC(I,3,K)-CC(IC,2,K)
- TI4 = CC(I,5,K)+CC(IC,4,K)
- TI3 = CC(I,5,K)-CC(IC,4,K)
- TR5 = CC(I-1,3,K)-CC(IC-1,2,K)
- TR2 = CC(I-1,3,K)+CC(IC-1,2,K)
- TR4 = CC(I-1,5,K)-CC(IC-1,4,K)
- TR3 = CC(I-1,5,K)+CC(IC-1,4,K)
- CH(I-1,K,1) = CC(I-1,1,K)+TR2+TR3
- CH(I,K,1) = CC(I,1,K)+TI2+TI3
- CR2 = CC(I-1,1,K)+TR11*TR2+TR12*TR3
- CI2 = CC(I,1,K)+TR11*TI2+TR12*TI3
- CR3 = CC(I-1,1,K)+TR12*TR2+TR11*TR3
- CI3 = CC(I,1,K)+TR12*TI2+TR11*TI3
- CR5 = TI11*TR5+TI12*TR4
- CI5 = TI11*TI5+TI12*TI4
- CR4 = TI12*TR5-TI11*TR4
- CI4 = TI12*TI5-TI11*TI4
- DR3 = CR3-CI4
- DR4 = CR3+CI4
- DI3 = CI3+CR4
- DI4 = CI3-CR4
- DR5 = CR2+CI5
- DR2 = CR2-CI5
- DI5 = CI2-CR5
- DI2 = CI2+CR5
- CH(I-1,K,2) = WA1(I-2)*DR2-WA1(I-1)*DI2
- CH(I,K,2) = WA1(I-2)*DI2+WA1(I-1)*DR2
- CH(I-1,K,3) = WA2(I-2)*DR3-WA2(I-1)*DI3
- CH(I,K,3) = WA2(I-2)*DI3+WA2(I-1)*DR3
- CH(I-1,K,4) = WA3(I-2)*DR4-WA3(I-1)*DI4
- CH(I,K,4) = WA3(I-2)*DI4+WA3(I-1)*DR4
- CH(I-1,K,5) = WA4(I-2)*DR5-WA4(I-1)*DI5
- CH(I,K,5) = WA4(I-2)*DI5+WA4(I-1)*DR5
- 105 CONTINUE
- 106 CONTINUE
- RETURN
- END