+++ /dev/null
-*DECK RADF2
- SUBROUTINE RADF2 (IDO, L1, CC, CH, WA1)
-C***BEGIN PROLOGUE RADF2
-C***SUBSIDIARY
-C***PURPOSE Calculate the fast Fourier transform of subvectors of
-C length two.
-C***LIBRARY SLATEC (FFTPACK)
-C***TYPE SINGLE PRECISION (RADF2-S)
-C***AUTHOR Swarztrauber, P. N., (NCAR)
-C***ROUTINES CALLED (NONE)
-C***REVISION HISTORY (YYMMDD)
-C 790601 DATE WRITTEN
-C 830401 Modified to use SLATEC library source file format.
-C 860115 Modified by Ron Boisvert to adhere to Fortran 77 by
-C changing dummy array size declarations (1) to (*).
-C 881128 Modified by Dick Valent to meet prologue standards.
-C 890831 Modified array declarations. (WRB)
-C 891214 Prologue converted to Version 4.0 format. (BAB)
-C 900402 Added TYPE section. (WRB)
-C***END PROLOGUE RADF2
- DIMENSION CH(IDO,2,*), CC(IDO,L1,2), WA1(*)
-C***FIRST EXECUTABLE STATEMENT RADF2
- DO 101 K=1,L1
- CH(1,1,K) = CC(1,K,1)+CC(1,K,2)
- CH(IDO,2,K) = CC(1,K,1)-CC(1,K,2)
- 101 CONTINUE
- IF (IDO-2) 107,105,102
- 102 IDP2 = IDO+2
- IF((IDO-1)/2.LT.L1) GO TO 108
- DO 104 K=1,L1
-CDIR$ IVDEP
- DO 103 I=3,IDO,2
- IC = IDP2-I
- TR2 = WA1(I-2)*CC(I-1,K,2)+WA1(I-1)*CC(I,K,2)
- TI2 = WA1(I-2)*CC(I,K,2)-WA1(I-1)*CC(I-1,K,2)
- CH(I,1,K) = CC(I,K,1)+TI2
- CH(IC,2,K) = TI2-CC(I,K,1)
- CH(I-1,1,K) = CC(I-1,K,1)+TR2
- CH(IC-1,2,K) = CC(I-1,K,1)-TR2
- 103 CONTINUE
- 104 CONTINUE
- GO TO 111
- 108 DO 110 I=3,IDO,2
- IC = IDP2-I
-CDIR$ IVDEP
- DO 109 K=1,L1
- TR2 = WA1(I-2)*CC(I-1,K,2)+WA1(I-1)*CC(I,K,2)
- TI2 = WA1(I-2)*CC(I,K,2)-WA1(I-1)*CC(I-1,K,2)
- CH(I,1,K) = CC(I,K,1)+TI2
- CH(IC,2,K) = TI2-CC(I,K,1)
- CH(I-1,1,K) = CC(I-1,K,1)+TR2
- CH(IC-1,2,K) = CC(I-1,K,1)-TR2
- 109 CONTINUE
- 110 CONTINUE
- 111 IF (MOD(IDO,2) .EQ. 1) RETURN
- 105 DO 106 K=1,L1
- CH(1,2,K) = -CC(IDO,K,2)
- CH(IDO,1,K) = CC(IDO,K,1)
- 106 CONTINUE
- 107 RETURN
- END